(4x-1)(x^2-12x-12)=0

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Solution for (4x-1)(x^2-12x-12)=0 equation: 


Simplifying
(4x + -1)(x2 + -12x + -12) = 0

Reorder the terms:
(-1 + 4x)(x2 + -12x + -12) = 0

Reorder the terms:
(-1 + 4x)(-12 + -12x + x2) = 0

Multiply (-1 + 4x) * (-12 + -12x + x2)
(-1(-12 + -12x + x2) + 4x * (-12 + -12x + x2)) = 0
((-12 * -1 + -12x * -1 + x2 * -1) + 4x * (-12 + -12x + x2)) = 0
((12 + 12x + -1x2) + 4x * (-12 + -12x + x2)) = 0
(12 + 12x + -1x2 + (-12 * 4x + -12x * 4x + x2 * 4x)) = 0
(12 + 12x + -1x2 + (-48x + -48x2 + 4x3)) = 0

Reorder the terms:
(12 + 12x + -48x + -1x2 + -48x2 + 4x3) = 0

Combine like terms: 12x + -48x = -36x
(12 + -36x + -1x2 + -48x2 + 4x3) = 0

Combine like terms: -1x2 + -48x2 = -49x2
(12 + -36x + -49x2 + 4x3) = 0

Solving
12 + -36x + -49x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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